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Proof step 5 from proof osc-intro (conclusion)

⊦ ¬ (∀ s1, s11, s22. ∀ ev. view(ev) ≠ C ∧ reachable(trans, s1) ∧ reachable(trans, s11) ∧ trans(s11, ev, s22) ∧ eqstate(s11, s1) → (∃ s2. ∃ tr. proj(tr, Cview(view)) = [] ∧ proj(tr, Vview(view)) = proj(ev ', Vview(view)) ∧ trans∃(trans, s1, tr, s2) ∧ eqstate(s22, s2))) → ¬ osc(view, trans, eqstate)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
osc(view, trans, eqstate), reachable(trans, s1), reachable(trans, s0), trans(s0, ev, s), eqstate(s0, s1) ⊦ view(ev) = C, ∃ s2, tr. proj(tr, Cview(view)) = [] ∧ proj(tr, Vview(view)) = proj(ev ', Vview(view)) ∧ trans∃(trans, s1, tr, s2) ∧ eqstate(s, s2)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]