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Proof step 90 from proof aux-known (conclusion)

⊦ (a0[r => o] * R)[rs, f, g] ↔ (a1[r => o] * R)[rs, f, g(r ; a1)] ∧ g(r) = a0

User applied rule case distinction

And obtained the following new goals

Proof step 44:
(a0[r => o] * R)[rs, f, g] ⊦ (a1[r => o] * R)[rs, f, g(r ; a1)] ∧ g(r) = a0

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]