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Proof step 24 from proof lift-ex-r (
previous step
)
⊦ (a[_∃ rP])(Ha) ↔ (∃ r. (a[rP(r)])(Ha))
User applied rule case distinction
And obtained the following new goals
Proof step 9
:
(a[_∃ rP])(Ha) ⊦ ∃ r. (a[rP(r)])(Ha)
Rule argument
[CASEDARG : pos: right 1, ()]
Additional information
[[CONCRETESIMPRULES : ()]]