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Proof step 36 from proof merge-owned (conclusion)

⊦ (a[P] * R)[rs, f, g] ∧ (a0[P0] * R0)[rs, f, g] ∧ a0 ≠ a → (a[P] * a0[P0] * true)[rs, f, g]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
(a0[P0] * R0)[rs, f, g], (a[P] * R)[rs, f, g] ⊦ a0 = a, (a[P] * a0[P0] * true)[rs, f, g]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]