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Proof step 121 from proof write-known (previous step)

⊦ (a[r => o0] * R)[rs, f, g] ↔ (a[r => o1] * R)[rs, f(r ; o1), g] ∧ f(r) = o0

User applied rule case distinction

And obtained the following new goals

Proof step 74:
(a[r => o0] * R)[rs, f, g] ⊦ (a[r => o1] * R)[rs, f(r ; o1), g] ∧ f(r) = o0

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]