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Proof step 11 from proof and-combine (previous step)

precise(P0), P1(H0), P0(H0), H ⊥ H0 ⊦ (P * (P0 ∧ P1))(H ∪ H0) ↔ P(H)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ P0 * P1 = P1 * P0

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: sep-com antecedent: succedent: P0 * P1 = P1 * P0 substlist: [P1, P0] → [P0 ∧ P1, P] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0, 1, 0, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (P0 ∧ P1, P)]]