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Proof step 48 from proof introduce-sharing (conclusion)

⊦ (P0 ⊗ P1)(H) ↔ (∃ P. ((P -* P0) * (P -* P1) * P)(H))

User applied rule case distinction

And obtained the following new goals

Proof step 25:
(P0 ⊗ P1)(H) ⊦ ∃ P. ((P -* P0) * (P -* P1) * P)(H)

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]