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Proof step 9 from proof prop-shift (conclusion)

⊦ (⌜bv⌝ ∧ P0) * P1 = (⌜bv⌝ ∧ P0 * P1)

User applied rule expand right

And closed the goal!

Rule argument

[fmapos-arg: pos: right 1]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : and, , , ⊦ (P0 ∧ P1)(H) ↔ ¬ ¬ (P0(H) ∧ P1(H))], [CSIMPNAMEDSEQ : prop, , , ⊦ ⌜bv⌝ (H) ↔ bv], [CSIMPNAMEDSEQ : and-ass, , , ⊦ ((P0 ∧ P1) ∧ P2) = (P0 ∧ P1 ∧ P2)], [CSIMPNAMEDSEQ : and-com, , , ⊦ (P0 ∧ P1) = (P1 ∧ P0)], [CSIMPNAMEDSEQ : sep-ass, , , ⊦ (P0 * P1) * P2 = P0 * P1 * P2], [CSIMPNAMEDSEQ : sep-com, , , ⊦ P0 * P1 = P1 * P0], [CSIMPNAMEDSEQ : and-imp, , , ⊦ (P * (P1 ∧ P2))(H) → (P * P1)(H)], [CSIMPNAMEDSEQ : prop-sep, , , ⊦ ((⌜bv⌝ ∧ P0) * P1)(H) ↔ bv ∧ (P0 * P1)(H)])]]