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Proof step 26 from proof sep-ass (conclusion)

⊦ (P0 * P1) * P2 = P0 * P1 * P2

User applied rule expand right

And obtained the following new goals

Proof step 25:
⊦ ((P0 * P1) * P2)(H) ↔ (P0 * P1 * P2)(H)

Rule argument

[fmapos-arg: pos: right 1]

Additional information

[[CONCRETESIMPRULES : ()]]