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Proof step 15 from proof disj-write (previous step)

⊦ r = null, H0 ⊥ (H1 ++ r)[r, o] ↔ H0 ⊥ H1 ∧ ¬ r ∈ H0, r ∈ H1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ H0 ⊥ H1 ↔ (∀ r. ¬ r ∈ H0 ∨ ¬ r ∈ H1)

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: disj antecedent: succedent: H0 ⊥ H1 ↔ (∀ r. ¬ r ∈ H0 ∨ ¬ r ∈ H1) substlist: [H1, H0] → [(H1 ++ r)[r, o], H0] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 1, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : ((H1 ++ r)[r, o], H0)]]