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Proof step 22 from proof exin-uni (previous step)

r ∈ H ⊦ ∃ H0, o. H = H0 ∪ (∅ ++ r)[r, o] ∧ ¬ r ∈ H0, r = null

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nonnull, , , ⊦ r ∈ H → r ≠ null])]]