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Proof step 23 from proof sw-alloc-put (conclusion)

¬ r0 ∈ H, r0 ≠ null, r1 ∈ H ⊦ r0 ≠ r1 → ((H ++ r0)[r0, o0][r1, o1]) = (H[r1, o1] ++ r0)[r0, o0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
r1 ∈ H ⊦ ((H ++ r0)[r0, o0][r1, o1]) = (H[r1, o1] ++ r0)[r0, o0], r0 = null, r0 ∈ H

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]