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Proof step 31 from proof sw-del-add-new (conclusion)

¬ r ∈ H, r ≠ null ⊦ ¬ r ∈ rs → (H ++ r)[r, o] \ rs = ((H \ rs) ++ r)[r, o]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
⊦ r = null, (H ++ r)[r, o] \ rs = ((H \ rs) ++ r)[r, o], r ∈ H, r ∈ rs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]