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Proof step 11 from proof And-discard (previous step)

∀ s0, P. # s0 < # s → (true → # s0 = 0 ∨ s0 = ∅ ∨ (λ a. P) ∧_ s0 = P) ⊦ (λ a. P) ∧_ s = P, s = ∅, # s = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2)

Rule argument

[x0lemmaarg: spec-name: set-union instance-name: lemma-name: ext antecedent: succedent: s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) substlist: [s2, s1] → [∅, s] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((1, 0, 1)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (∅, s)]]