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Proof step 13 from proof And-discard (previous step)

⊦ # s = 0, s = ∅, (λ a. P) ∧_ s = P

User applied rule induction

And obtained the following new goals

Proof step 12:
true, ∀ s0, P. # s0 < # s → (true → # s0 = 0 ∨ s0 = ∅ ∨ (λ a. P) ∧_ s0 = P) ⊦ # s = 0 ∨ s = ∅ ∨ (λ a. P) ∧_ s = P

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, # s, [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (# s)]]