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Proof step 15 from proof And-forall (previous step)

(aP0 ∧_ s)(H), ∀ a, H. a ∈ s ∧ aP0(a)(H) → aP(a)(H), ∀ s0, aP0, H, aP. # s0 < # s → ((aP0 ∧_ s0)(H) ∧ (∀ a, H. a ∈ s0 ∧ aP0(a)(H) → aP(a)(H)) → (aP ∧_ s0)(H)) ⊦ (aP ∧_ s)(H)

User applied rule cut formula

And closed the goal!

Rule argument

[fma-arg: s = ∅]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : And-emp, , , ⊦ aP ∧_ ∅ = true], [CSIMPSEQ : ⊦ true(H)])], [EXTRAFMAS : (s = ∅)]]