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Proof step 10 from proof And-discard (previous step)

⊦ st = ∅, (λ a, d. P) ∧_ st = P

User applied rule induction

And obtained the following new goals

Proof step 9:
true, ∀ st0, P. # st0 < # st → (true → st0 = ∅ ∨ (λ a, d. P) ∧_ st0 = P) ⊦ st = ∅ ∨ (λ a, d. P) ∧_ st = P

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, # st, [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (# st)]]