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Proof step 10 from proof ls-unfold1 (conclusion)

r ≠ null ⊦ H[r] = ce → (¬ ¬ (ls(r, x) * P)(H) ↔ (∃ a, y, r0. (r => a × r0 * ls(r0, y) * P)(H) ∧ x = a ' + y))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ r = null, (ls(r, x) * P)(H) ↔ (∃ a, y, r0. (r => a × r0 * ls(r0, y) * P)(H) ∧ x = a ' + y)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]