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Proof step 5 from proof ll-trav2-end (previous step)

(ll-trav(r0, r1, r2, x) * P)(H), H[r2] = a × null ⊦ x ≠ [], r2 = null

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
H[r2] = a × null, (ll-trav(r0, r1, r2, []) * P)(H) ⊦ r2 = null

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]