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Proof step 11 from proof lls-fold-tail (conclusion)

x ≠ [] ⊦ (r1 => x .last × r2 * lls(r0, r1, x .butlast) * P)(H) → (¬ (lls(r0, r2, x) * P)(H) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
(r1 => x .last × r2 * lls(r0, r1, x .butlast) * P)(H) ⊦ x = [], (lls(r0, r2, x) * P)(H)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]