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Proof step 2 from proof tr-branch (conclusion)

⊦ (tr(r, t) * P)(H) ∧ r ≠ null → t ≠ leaf

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : tr-base, , , ⊦ tr(r, leaf) = (emp ∧ ⌜r = null⌝ )], [CSIMPSEQ : ⊦ ¬ false(H)], [CSIMPSEQ : ⊦ P0 * P1 = P1 * P0], [CSIMPSEQ : ⊦ (P0 * P1) * P2 = P0 * P1 * P2], [CSIMPSEQ : ⊦ false * P = false], [CSIMPSEQ : ⊦ (P0 ∧ P1) = (P1 ∧ P0)], [CSIMPSEQ : ⊦ ((P0 ∧ P1) ∧ P2) = (P0 ∧ P1 ∧ P2)], [CSIMPSEQ : ⊦ (false ∧ P) = false], [CSIMPSEQ : ⊦ ⌜false⌝ = false])]]