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Proof step 59 from proof map-putex (conclusion)
r ∈ H ⊦ (r => o0 * P)(H[r, o1]) ↔ ¬ ¬ (o0 = o1 ∧ (r =>_ * P)(H))
User applied rule case distinction
And obtained the following new goals
Proof step 36
:
(r => o0 * P)(H[r, o1]), r ∈ H ⊦ ¬ ¬ (o0 = o1 ∧ (r =>_ * P)(H))
Rule argument
[CASEDARG : pos: right 1, ()]
Additional information
[[CONCRETESIMPRULES : ()]]