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Proof step 11 from proof alloc (previous step)

P(H) ⊦ ⟪H0 := H⟫ ⟪choose r1 with (¬ r1 ∈ H0 ∧ r1 ≠ null) in r0 := r1, H0 := H0 ++ r1⟫ (r0 =>_ * P)(H0)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 10:
P(H), H1 = H ⊦ ⟪choose r1 with (¬ r1 ∈ H1 ∧ r1 ≠ null) in r0 := r1, H1 := H1 ++ r1⟫ (r0 =>_ * P)(H1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]