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Proof step 3 from proof read-known (previous step)

(r => o0 * P)(H) ⊦ ⟪o := o1⟫ ⟪if ¬ r ∈ H then abort else o := H[r]⟫ o0 = o

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 2:
(r => o0 * P)(H), o2 = o1 ⊦ ⟪if ¬ r ∈ H then abort else o2 := H[r]⟫ o0 = o2

Rule argument

[emptyarg]

Additional information

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