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Proof step 23 from proof rely-owns-one (conclusion)

⊦ rely(a, rs, f, g, rs0, f0, g0) → (owns-one(a, r, rs, g) ↔ owns-one(a, r, rs0, g0))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : rely, , , ⊦ rely (a, rs0, f0, g0, rs1, f1, g1) ↔ (∀ r. ( g0(r) = a ∧ r ∈ rs0 ↔ g1(r) = a ∧ r ∈ rs1) ∧ ( g0(r) = a ∧ r ∈ rs0 → f0(r) = f1(r)))])]]