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Proof step 4 from proof alloc (conclusion)

⊦ r ≠ null ∧ ¬ r ∈ H1 ∧ rely(me, O1(r ; me), H1 ++ r, O2, H2) → ((P0 * true)(H1) ↔ (!(me, O2, r =>_) * P0 * true)(H1 ++ r))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
rely(me, O1(r ; me), H1 ++ r, O2, H2) ⊦ r = null, (P0 * true)(H1) ↔ (!(me, O2, r =>_) * P0 * true)(H1 ++ r), r ∈ H1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]