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Proof step 10 from proof split-old (previous step)

(↓ (P0 * P1))(H, H0) ⊦ (↓ P0 * ↓ P1)(H, H0)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : old, , , ⊦ (↓ P)(H0, H1) ↔ P(H0)])]]