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Proof step 15 from proof split-old (conclusion)
⊦ ↓ (P0 * P1) = ↓ P0 * ↓ P1
User applied rule expand right
And obtained the following new goals
Proof step 14
:
⊦ (↓ (P0 * P1))(H, H0) ↔ (↓ P0 * ↓ P1)(H, H0)
Rule argument
[fmapos-arg: pos: right 1]
Additional information
[[CONCRETESIMPRULES : ()]]