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Proof step 4 from proof split-union (conclusion)

⊦ R0(H0, H1) ∧ R1(H2, H3) ∧ H0 ⊥ H2 ∧ H1 ⊥ H3 → (¬ (R0 * R1)(H0 ∪ H2, H1 ∪ H3) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]