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Proof step 15 from proof rg-blocked1-not-r1-unfair (previous step)

□ (¬ last ∧ ¬ blocked), \E ∃ S0. S0 = s, R2(pm, S', S'') -+-> G2(pm, S, S'), RG-restr(pm, R1, G1, Pre1, Post1, I, R2, G2, Pre2, Post2), R1(pm, s0, S), I(pm, s0), Pre1(pm, s1), Pre2(pm, s1), I(pm, S), I(pm, s1), ¬ R1(pm, s0, s) ⊦ (R1(pm, S', S'') ∧ R2(pm, S', S'')) -+-> (G1(pm, S, S') ∨ G2(pm, S, S'))

User applied rule decompose

And closed the goal!

Rule argument

positions: 3, 1

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