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Proof step 5 from proof CInitto-Idle-less (previous step)

n1 + 1 ≤ n0 → CInit(n1 + 1, act, cs), n1 < n0 ⊦ n0 = 0, Idle(n1 + 1, cs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n1 < n0, CInit(n1 + 1, act, cs) ⊦ n0 = 0, Idle(n1 + 1, cs)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%succ-01: ⊦ m + 1 ≤ n ↔ m < n; from specification nat