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Proof step 7 from proof CInittosucc-Cinittp (previous step)

m ≤ n0, ∀ m0. m0 ≤ n0 + 1 → CInit(m0, act, cs) ⊦ CInit(m, act, cs)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m

Additional information

Used simplifier rules: lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%l-02: ⊦ ¬ m + n < m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: m