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Proof step 4 from proof CRelytosucc-CRely (previous step)

∀ m0. m0 ≤ m + 1 → CRely(m0, act, cs, act0, cs0) ⊦ CRely(m + 1, act, cs, act0, cs0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: m + 1

Additional information

Used simplifier rules: lep-02: ⊦ m + n ≤ m + n0 ↔ n ≤ n0; from specification nat%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: m + 1