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Proof step 11 from proof CSEQ-sat-rely-guar (previous step)

⊦ CGuar(m, act, cs, act0, cs0) ↔ Guar(m, cs, cs0) ∧ ((¬ act(m) → Idle(m, cs)) → ¬ act0(m) → Idle(m, cs0)) ∧ (∀ m0. m0 ≠ m → (act0(m0) ↔ act(m0)) ∧ (Idle(m0, cs) ↔ Idle(m0, cs0)))

A spec-lemma