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Proof step 3 from proof RG-restr-ok (previous step)

⊦ RG-restr(n2, R1, G1, Pre1, Post1, IV, R2, G2, Pre2, Post2) ↔ ¬ ¬ ( (∀ act, cs, act4, cs4. (Pre1(n2, act, cs) ∧ R1(n2, act, cs, act4, cs4) → Pre1(n2, act4, cs4)) ∧ (R1(n2, act, cs, act4, cs4) ∧ IV(n2, act, cs) → IV(n2, act4, cs4)) ∧ (R2(n2, act, cs, act4, cs4) ∧ IV(n2, act, cs) → IV(n2, act4, cs4)) ∧ (Pre2(n2, act, cs) ∧ R2(n2, act, cs, act4, cs4) → Pre2(n2, act4, cs4)) ∧ (G1(n2, act, cs, act4, cs4) ∧ IV(n2, act, cs) → R2(n2, act, cs, act4, cs4)) ∧ (G2(n2, act, cs, act4, cs4) ∧ IV(n2, act, cs) → R1(n2, act, cs, act4, cs4))) ∧ (∀ act, cs, act4, cs4, act5, cs5. (Pre1(n2, act, cs) ∧ Post1(n2, act, cs, act4, cs4) ∧ IV(n2, act4, cs4) ∧ R1(n2, act4, cs4, act5, cs5) → Post1(n2, act, cs, act5, cs5)) ∧ (Pre2(n2, act, cs) ∧ Post2(n2, act, cs, act4, cs4) ∧ IV(n2, act4, cs4) ∧ R2(n2, act4, cs4, act5, cs5) → Post2(n2, act, cs, act5, cs5)) ∧ (R1(n2, act, cs, act4, cs4) ∧ R1(n2, act4, cs4, act5, cs5) ∧ IV(n2, act, cs) → R1(n2, act, cs, act5, cs5)) ∧ (R2(n2, act, cs, act4, cs4) ∧ R2(n2, act4, cs4, act5, cs5) ∧ IV(n2, act, cs) → R2(n2, act, cs, act5, cs5))) ∧ (∀ act, cs. (IV(n2, act, cs) → R1(n2, act, cs, act, cs) ∧ R2(n2, act, cs, act, cs)) ∧ (Pre1(n2, act, cs) → IV(n2, act, cs)) ∧ (Pre2(n2, act, cs) → IV(n2, act, cs))))

A spec-lemma