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Proof step 7 from proof set-branch (previous step)

⊦ branch(t0, a, t1).set = (t1.set ∪ t0.set) ++ a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2)

Rule argument

spec: set-basic inst: name: Extension seq: ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) subst: [s2, s1] → [(t1.set ∪ t0.set) ++ a, branch(t0, a, t1).set] flags: rewrite

Additional information

[Concretesimprules(()), Extraterms(((t1.set ∪ t0.set) ++ abranch(t0, a, t1).set))]