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Proof step 6 from proof set-min (previous step)

bst(t), t.leftmost ∈ t ⊦ t.set.min = t.leftmost, t = leaf

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 1:
a ∈ s, ∀ b. b ∈ s → ¬ b < a ⊦ a = s.min

Rule argument

spec: oset inst: name: min-q seq: a ∈ s, ∀ b. b ∈ s → ¬ b < a ⊦ a = s.min subst: [a, s] → [t.leftmost, t.set] flags: []

Additional information

[Concretesimprules(()), Extraterms((t.leftmostt.set))]