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Proof step 55 from proof insert-bst (conclusion)

bst(t) ⊦ ¬ bst(t.insert(a)) ↔ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 54:
bst(t) ⊦ bst(t.insert(a))

Rule argument

Additional information

[Concretesimprules(())]