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Proof step 27 from proof ismin (conclusion)

⊦ t ≠ leaf ∧ bst(t) ∧ b ≠ t .leftmost ∧ b ∈ t → t .leftmost < b

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
bst(t), b ∈ t, b < t .leftmost ⊦ b = t .leftmost, t = leaf

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ a ≠ b → (¬ a < b ↔ b < a)])]]