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Proof step 5 from proof program+leftmost (previous step)

r ≠ null, (r => mknode(r0, a0, r1) * tr(r0, t0) * tr(r1, t1) * P)(H), r2 = H[r] .left, H1 = H ∧ r3 = r, r2 = null ⊦ 〈a1 := H1[r3] .val〉〈r3 := H1[r3] .right〉 ((tr(r3, (t0 = leaf ⊃ t1; branch(t0 .butleftmost, a0, t1))) * P * true)(H1) ∧ a1 = ((t0 = leaf ⊃ a0; t0 .leftmost)))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 4:
r ≠ null, (r => mknode(r0, a0, r1) * tr(r0, t0) * tr(r1, t1) * P)(H), r2 = H[r] .left, H1 = H ∧ r3 = r, r2 = null ⊦ 〈r := H1[r3] .right〉 ((tr(r, (t0 = leaf ⊃ t1; branch(t0 .butleftmost, a0, t1))) * P * true)(H1) ∧ H1[r3] .val = ((t0 = leaf ⊃ a0; t0 .leftmost)))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]