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Proof step 4 from proof root-nonnull (conclusion)

⊦ r ≠ null ∧ ((tr(r, t) * P))(H) → (∃ t0, a, t1. t = branch(t0, a, t1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
((tr(r, t) * P))(H) ⊦ r = null, ∃ t0, a, t1. t = branch(t0, a, t1)

Rule argument

Additional information

[Concretesimprules(())]