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Proof step 16 from proof finz-add-bigger (previous step)

(2^ #fz(m + 2^ #fz(m)) * 2^ n) * lead(m) + 2^ #fz(m + 2^ #fz(m)) * 2^ n = 2^ #fz(m + 2^ #fz(m)) * lead(m + 2^ #fz(m)), odd(lead(m)), odd(lead(m + 2^ #fz(m))) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
2^ n + lead(m) * 2^ n = lead(m + 2^ #fz(m)), odd(lead(m)), odd(2^ n + lead(m) * 2^ n) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m * n = n * m], [CSIMPSEQ : ⊦ m0 * m * n = (m0 * m) * n], [CSIMPSEQ : ⊦ 2^ n ≠ 0], [CSIMPSEQ : ⊦ m * n + m0 * n = m1 * n ↔ ¬ ¬ (m + m0 = m1 ∨ n = 0)], [CSIMPSEQ : ⊦ m + n = n + m])]]