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Proof step 20 from proof finz-add-bigger (previous step)

(m + 1) + 2^ #fz(m) = 2^ #fz(m + 2^ #fz(m)) * lead(m + 2^ #fz(m)), #fz(m + 2^ #fz(m)) + n = #fz(m), m + 1 = (2^ #fz(m + 2^ #fz(m)) * 2^ n) * lead(m), (m + 2^ #fz(m)) + 1 = 2^ #fz(m + 2^ #fz(m)) * lead(m + 2^ #fz(m)), odd(lead(m)), odd(lead(m + 2^ #fz(m))) ⊦

User applied rule weakening

And obtained the following new goals

Proof step 19:
(m + 1) + 2^ #fz(m) = 2^ #fz(m + 2^ #fz(m)) * lead(m + 2^ #fz(m)), #fz(m + 2^ #fz(m)) + n = #fz(m), m + 1 = (2^ #fz(m + 2^ #fz(m)) * 2^ n) * lead(m), odd(lead(m)), odd(lead(m + 2^ #fz(m))) ⊦

Rule argument

[fmaposlist-arg: (pos: left 4)]

Additional information

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