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Proof step 26 from proof finz-add-bigger (previous step)

odd(lead(m)), (m + 2^ #fz(m)) + 1 = 2^ #fz(m + 2^ #fz(m)) * lead(m + 2^ #fz(m)), m + 1 = 2^ #fz(m) * lead(m), #fz(m + 2^ #fz(m)) ≤ #fz(m) ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ odd(lead(n))
Proof step 25:
odd(lead(m + 2^ #fz(m))), odd(lead(m)), (m + 2^ #fz(m)) + 1 = 2^ #fz(m + 2^ #fz(m)) * lead(m + 2^ #fz(m)), m + 1 = 2^ #fz(m) * lead(m), #fz(m + 2^ #fz(m)) ≤ #fz(m) ⊦

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: lead-is-odd antecedent: succedent: odd(lead(n)) substlist: [n] → [m + 2^ #fz(m)] add preconditions?: F is rewrite lemma?: F current spec?: T rotate lemma?: F replace all?: F paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (m + 2^ #fz(m))]]