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Proof step 10 from proof finz-bigger (previous step)

m0 + 1 = 2^ m2 * 2 * m + 2^ m2, #fz(m0) < m2, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦

User applied rule apply induction

And closed the goal!

Rule argument

[substlist-arg: [m1, n, n0] → [m0, 2 * m + 1, m2]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m * (n + 1) = m * n + m], [CSIMPSEQ : ⊦ m + m = 2 * m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m], [CSIMPSEQ : ⊦ ¬ 2 * n < n], [CSIMPSEQ : ⊦ m0 * m * n = (m0 * m) * n], [CSIMPSEQ : ⊦ m * n = n * m])], [EXTRATERMS : (m0, 2 * m + 1, m2)]]