| 2 * m0 + 2 = 2 * 2^ m2 + 4 * 2^ m2 * m, #fz(m0) < m2, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦ 2 * m0 + 2 = (4 * m + 2) * 2^ m2 |
⊦ m0 * (m + n) = m0 * m + m0 * n
[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m0 * m * n = (m0 * m) * n], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ m * n = n * m])], [EXTRATERMS : (2^ m2, 2, 4 * m)]]