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Proof step 17 from proof finz-bigger (previous step)

2 * m0 + 2 = 2 * 2^ m2 + 4 * 2^ m2 * m, #fz(m0) < m2, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 13:
2 * (m0 + 1) = 2 * 2^ m2 * (1 + 2 * m), 2 * m0 + 2 = 2 * 2^ m2 + 4 * 2^ m2 * m, #fz(m0) < m2, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦
Proof step 16:
2 * m0 + 2 = 2 * 2^ m2 + 4 * 2^ m2 * m, #fz(m0) < m2, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦ 2 * (m0 + 1) = 2 * 2^ m2 * (1 + 2 * m)

Rule argument

[fma-arg: 2 * (m0 + 1) = 2 * 2^ m2 * (1 + 2 * m)]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (2 * (m0 + 1) = 2 * 2^ m2 * (1 + 2 * m))]]