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Proof step 23 from proof finz-bigger (previous step)

m0 + 1 = 2^ n0 * m, #fz(m0) + 1 < n0, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦

User applied rule apply induction

And closed the goal!

Rule argument

[substlist-arg: [m1, n, n0] → [m0, m, n0]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m < n → ¬ m + m0 < n], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ m + m = 2 * m], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m], [CSIMPSEQ : ⊦ ¬ 2 * n < n], [CSIMPSEQ : ⊦ m0 * m * n = (m0 * m) * n], [CSIMPSEQ : ⊦ m * n = n * m])], [EXTRATERMS : (m0, m, n0)]]