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Proof step 27 from proof finz-bigger (previous step)

2 * m0 + 2 = n * 2^ n0, #fz(m0) + 1 < n0, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 21:
odd(n), 2 * m0 + 2 = n * 2^ n0, #fz(m0) + 1 < n0, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦
Proof step 26:
2 * m0 + 2 = n * 2^ n0, #fz(m0) + 1 < n0, ∀ m1, n, n0. m1 < m0 + m0 + 1 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦ odd(n)

Rule argument

[fma-arg: odd(n)]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (odd(n))]]