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Proof step 3 from proof finz-bigger (previous step)

2 * m0 + 1 = n * 2^ n0, ∀ m1, n, n0. m1 < m0 + m0 → (m1 + 1 = n * 2^ n0 ∧ #fz(m1) < n0 → false) ⊦ n0 = 0

User applied rule constructor cut

And closed the goal!

Rule argument

[var-arg: n0]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : nat generated by 0, +1;], [CSIMPSEQ : ⊦ m +1 = m + 1], [CSIMPSEQ : ⊦ 2^ (n + 1) = 2 * 2^ n], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ n0 < n → ( m * n + n0 = m0 * n ↔ m = m0 ∧ n0 = 0)], [CSIMPSEQ : ⊦ m0 * m * n = (m0 * m) * n], [CSIMPSEQ : ⊦ m * n = n * m])]]